Complex Number Long Division Calculator
Complex Number Long Division Calculator
Output: complex quotient (real and imaginary).
The Complex Number Long Division Calculator divides one complex number by another and returns the result in a + bi form. Because you cannot divide directly by an imaginary part, the method multiplies the numerator and denominator by the conjugate of the divisor, which turns the denominator into a real number. The calculator then separates the real and imaginary parts, simplifies each, and shows every step. Enter a dividend and divisor as a + bi to see the conjugate multiplication, the expanded numerator, the real denominator, and the final quotient with its real and imaginary components.
How to use the Complex Number Long Division Calculator
To divide complex numbers, follow these 4 steps:
- Enter the dividend as a + bi (for example, 3 + 2i).
- Enter the divisor as c + di (for example, 1 − i).
- Click Calculate to multiply by the conjugate and simplify.
- Read the quotient's real part and imaginary part with each step shown.
The calculator forms the conjugate of the divisor automatically, so you only enter the two complex numbers and read the a + bi answer.
Why complex division uses the conjugate
A complex number a + bi has a real part a and an imaginary part b, where i² = −1. You cannot leave an imaginary number in a denominator, so complex division rationalizes it. The conjugate of c + di is c − di, and multiplying a complex number by its conjugate gives c² + d², a real number, because the imaginary cross-terms cancel. The Complex Number Long Division Calculator uses this to convert a complex divisor into a real one, after which each part of the quotient is a straightforward real division.
Division shares a total into equal groups. Long division does this digit by digit.
Divisor (32) — the number you divide by. Place it to the left of the bracket.
How complex number division works
The calculator produces the a + bi quotient through five internal actions:
- Forms the conjugate of the divisor by flipping the sign of its imaginary part.
- Multiplies both numerator and divisor by that conjugate.
- Expands the numerator with the FOIL rule, replacing i² with −1.
- Simplifies the denominator to the real value c² + d².
- Divides the real and imaginary parts of the numerator by that real denominator.
Once the denominator is real, finding each part of the quotient is ordinary division, so the answer resolves cleanly into a + bi form.
Forms the conjugate of the divisor by flipping the sign of its imaginary part.
Complex division formula
The Complex Number Long Division Calculator uses (a + bi) ÷ (c + di) = [(a + bi)(c − di)] / (c² + d²), which expands to [(ac + bd) + (bc − ad)i] / (c² + d²). The denominator c² + d² is the squared modulus of the divisor. For (3 + 2i) ÷ (1 − i), the denominator is 1² + (−1)² = 2.
Complex number example problems
These examples show conjugate multiplication and separating real and imaginary parts.
Example 1 — (3 + 2i) ÷ (1 − i)
- Multiply top and bottom by the conjugate 1 + i.
- Numerator: (3 + 2i)(1 + i) = 3 + 3i + 2i + 2i² = 1 + 5i; denominator: 1² + 1² = 2.
- So (3 + 2i) ÷ (1 − i) = 1/2 + 5/2 i = 0.5 + 2.5i.
Example 2 — Divide by a real number: (4 + 6i) ÷ 2
- The divisor 2 is already real, so no conjugate is needed.
- Divide each part by 2: 4/2 = 2 and 6/2 = 3.
- So (4 + 6i) ÷ 2 = 2 + 3i.
Example 3 — Divide by a pure imaginary: (2 + 3i) ÷ i
- The conjugate of i is −i; multiply top and bottom by −i.
- Numerator: (2 + 3i)(−i) = −2i − 3i² = 3 − 2i; denominator: i × −i = 1.
- So (2 + 3i) ÷ i = 3 − 2i.
Multiply top and bottom by the conjugate 1 + i. Numerator: (3 + 2i)(1 + i) = 3 + 3i + 2i + 2i² = 1 + 5i; denominator: 1² + 1² = 2. So (3 + 2i) ÷ (1 − i) = 1/2 + 5/2 i = 0.5 + 2.5i.
The divisor 2 is already real, so no conjugate is needed. Divide each part by 2: 4/2 = 2 and 6/2 = 3. So (4 + 6i) ÷ 2 = 2 + 3i.
The conjugate of i is −i; multiply top and bottom by −i. Numerator: (2 + 3i)(−i) = −2i − 3i² = 3 − 2i; denominator: i × −i = 1. So (2 + 3i) ÷ i = 3 − 2i.
Worked complex problems
How do you divide (5 + i) by (2 + 3i)?
(5 + i) ÷ (2 + 3i) = 1 − i. Multiply top and bottom by the conjugate 2 − 3i. Numerator: (5 + i)(2 − 3i) = 10 − 15i + 2i − 3i² = 13 − 13i. Denominator: 2² + 3² = 13. Dividing gives 13/13 − 13/13 i = 1 − i.
Why does the denominator become a real number?
Multiplying c + di by its conjugate c − di gives c² + d², which has no i. The cross terms +cdi and −cdi cancel, and −d²i² becomes +d² because i² = −1. This is why the conjugate is the right multiplier: it clears the imaginary part from the denominator so the quotient can be written as a + bi.
Common complex division mistakes
Complex number division produces 5 frequent errors:
- Multiplying by the divisor instead of its conjugate.
- Forgetting that i² = −1 when expanding the numerator.
- Changing the sign of the real part instead of the imaginary part in the conjugate.
- Dividing only one part of the numerator by the real denominator.
- Leaving an imaginary number in the denominator instead of rationalizing it.
The Complex Number Long Division Calculator forms the correct conjugate and substitutes i² = −1 automatically, so both parts of the quotient are exact.
Frequently Asked Questions
How do you divide complex numbers?
How do you divide complex numbers?
What is the conjugate of a complex number?
Why do you multiply by the conjugate when dividing?
How do you divide a complex number by a real number?
How do you divide by i?
What is the denominator c² + d²?
How do I check a complex division answer?
The relationship behind complex division
The Complex Number Long Division Calculator relies on (a + bi) ÷ (c + di) = [(a + bi)(c − di)] / (c² + d²), where the conjugate turns the denominator into the real squared modulus c² + d². As a check, quotient × divisor = dividend must hold: for (5 + i) ÷ (2 + 3i) = 1 − i, multiplying (1 − i)(2 + 3i) returns 5 + i.